1.

If the curves `2x^(2)+3y^(2)=6 and ax^(2)+4y^(2)=4` intersect orthogonally, then a =A. 2B. 1C. 3D. none of these

Answer» Correct Answer - A
We know that the curves
`(x^(2))/(a^(2))+(y^(2))/(b^(2))=1 and (x^(2))/(c^(2))+(y^(2))/(d^(2))=1`
intersect orthogonally iff `a^(2)-b^(2)=c^(2)-d^(2)`
Therefore, the curves `2x^(2)+3y^(2)=6 and ax^(2)+4y^(2) =4` will intersect orthogonally, if
`3-2=(4)/(a)-1 rArr 2=(4)/(a) rArr a =2`


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