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If the de - Broglie wavelengths for a proton and for a `alpha` - particle are equal , then the ratio of their velocities will beA. `4 : 1`B. `2 : 1`C. `1 : 2`D. `1 : 4`

Answer» Correct Answer - A
As `lambda = (n)/(mv) rArr lambda (1)/(m)`
Hence , `(lambda p)/(lambda alpha) = (m_(alpha) v_(alpha))/(m_(p) v_(p))/(m_(p) v_(p)) rArr (1)/(1) = ( m_(alpha) v_(alpha))/(m_(p) v_(p)) rArr (v_(p))/( v_(alpha)) = (m_(alpha))/(m_(p)) = (4)/(1)`


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