1.

If the density of some lake water is 1.2.5 g mL^(-1) and contains 92 g of Na^(+) ions per kg of water, calculate the molality of Na^(+) ions in the lake.

Answer»

Solution :No. of MOLES of `Na^(+)` ion
`= ("mass")/("molar Mass")`
`= (92 G)/(23g "mol"^(-2))`
= 4 mol
MOLARITY of `Na^(+)` ions = `("No. of moles of "Na^(+) ions)/("Mass of WATER in KG ")`
= `(4 " mol ")/(1 kg )`
` = 4 " mol " kg^(-1) = 4 `m.


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