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If the density of some lake water is "1.25 g mL"^(-) and contains "92 g of Na"^(+) ions per kg of water, calculate the molality of Na^(+) ions in the lake. |
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Answer» Solution :`"No. of moles in 92 g of Na"^(+) " ions "=("92 g")/("23 g MOL"^(-1))="4 moles(as atomic MASS of NA = 23)"` As these are present in 1 kg of WATER, by definition, MOLALITY = 4M. |
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