If the diameter of earth becomes two times the present value and its m

1.	If the diameter of earth becomes two times the present value and its mass remains unchanged; then how would the weight of an object on the surface of earth be affected?
Answer» Using F = \(\frac{GMm}{R^2}\) we have new weight given by F' = \(\frac{GMm}{(2R)^2}\) = \(\frac{1}{4}\)F \(\therefore\) Weight becomes one-fourth of the original value.

If the diameter of earth becomes two times the present value and its mass remains unchanged; then how would the weight of an object on the surface of earth be affected?

Answer»

Using F = \(\frac{GMm}{R^2}\)

we have new weight

given by F' = \(\frac{GMm}{(2R)^2}\) = \(\frac{1}{4}\)F

\(\therefore\) Weight becomes one-fourth of the original value.

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If the diameter of earth becomes two times the present value and its mass remains unchanged; then how would the weight of an object on the surface of earth be affected?

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