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If the dimension of a physical quantity are given by `M^a L^b T^c,` then the physical quantity will beA. Force if a = 0, b = –1, c = –2B. Pressure if a = 1, b = –1, c = –2C. Velocity if a = 1, b = 0, c = –1D. Acceleration if a = 1, b = 1, c = –2 |
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Answer» Correct Answer - B `[P]=(F)/(A)=[(MLT^(-2))/(L^(2))]=[ML^(-1)T^(-2)]` |
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