InterviewSolution
Saved Bookmarks
| 1. |
If the displacement of simple pendulum at any time is `0.02` m and acceleration is `2m//s^(2)`, then in this time angular velocity will beA. 100 rad/sB. 10 rad/sC. 1 rad/sD. `0.1` rad/s |
|
Answer» Correct Answer - B Acceleration `|alpha|=omega^(2)x` or `omega=sqrt(alpha)/(x)` `=sqrt((2)/(0.002))=10rad//s` |
|