1.

If the displacement of simple pendulum at any time is `0.02` m and acceleration is `2m//s^(2)`, then in this time angular velocity will beA. 100 rad/sB. 10 rad/sC. 1 rad/sD. `0.1` rad/s

Answer» Correct Answer - B
Acceleration `|alpha|=omega^(2)x`
or `omega=sqrt(alpha)/(x)`
`=sqrt((2)/(0.002))=10rad//s`


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