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if the displacement of the particle at an instant is given by `y = r sin (omega t - theta)` where r is amplitude of oscillation. `omega` is the angular velocity and `-theta` is the initial phase of the particle, then find the particle velocity and particle acceleration. |
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Answer» Correct Answer - `r omega cos (omega t - theta) ; - omega^2 y` `y =r sin (omegat = theta)` Velocity, `upsilon = (dy)/(dt) =r cos (omega t -theta)(d)/(dt)(omega t - theta) = r cos (omegat - theta)xx omega =r omega cos (omegat - theta)` Acceleration, `A =(d upsilon)/(dt) = r omega [-sin(omegat - theta)]xxomega=- omega^2 r sin (omegat - theta) =- omega^2 y` |
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