Evaluate `(1001)^(1/3)` upto six places of decimal. – InterviewSolution

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1.	Evaluate `(1001)^(1/3)` upto six places of decimal.
Answer» `(100)^(1//3) = (1000 +1)^(1//3) = [1000(1+(1)/(1000))]^(1//3) = 10 (1+001)^(1//3)` `= 10 [ 1+(1)/(3)(0.001)+((1)/(3)((1)/(3) - 1))/(2!) (.001)^2 +….] = 10 [ 1 + 0.0003333 - (1)/(9)(0.000001)+…..` `=10[1+ 0.00003333- 0.0000001]` ` = 10.003332`

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