A particle starts from rest and its angular displacement (in red) is g – InterviewSolution

InterviewSolution

1.	A particle starts from rest and its angular displacement (in red) is given by `theta = (t^2)/(20) +(t)/(5),` calculate the angular velocity at the end of t =4 second.
Answer» Correct Answer - ` 0.6 rad//s` Angular velocity `omega = (d theta)/(dt) = (d)/(dt)((t^2)/(20) + (t)/(5)) = (2t)/(20)+(1)/(5)` when t =4 s, `omega = (2xx4)/(20) +(1)/(5) = 0.6 rad//s`

Discussion

No Comment Found

Related InterviewSolutions

Evaluate `(1001)^(1/3)` upto six places of decimal.
A particle is at rest, It starts rotating about a fixed point. Its angle of rotation `(theta)` with time (t) is given by the relation : `theta = (6t^3)/(15) - (t^2)/(2)` where `theta` is in radian and t is seconds. Find the angular velocity and angular acceleration of a particle at the end of 6 second.
A particle starts from rest and its angular displacement (in red) is given by `theta = (t^2)/(20) +(t)/(5),` calculate the angular velocity at the end of t =4 second.
An inclined plane rises 1 in 10. if the length of the inclined plane is 5 cm.. Calculate the hight of the reised end above the horizontal.
Find the value of the following : (a) `sin 210^(@)` (b) `cos 220^(@)` (c ) `tan 245^(@)`
If `sin theta = 3//5,` find the values of cosine `theta` and tangent `theta.`
If `x = a cos theta` and `y = b sin theta`, find `(dy)/(dx)`
`Lt sin theta = ….. ("in radian") theta rarr 0`
Find the (i) surface area (ii) volume of the cylinder of length 10 cm and radius 2cm.
Simplify the following : (i) `(0.05246)^(1//8) - 2.6055` (ii) `(3.142xx(80.2)^(1//2))/((9.8)^(1//2)`