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If the distance between the plane Ax 2y + z = d and the plane containing the lines2 1x=3 2y=4 3zand3 2x=4 3y=5 4zis 6 , then |d| isA. `3`B. 4C. 6D. 1 |
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Answer» Correct Answer - C The equation of the plane containing the given lines is `|(x-1,y-2,z-3),(2,3,4),(3,4,5)|=0impliesx-2y+z=0` This plane is at a distance of `sqrt(6)` units from the plane `Ax-2y+z=d`. `:.A=1` and `(|d-0|)/(sqrt(1+4+1))=sqrt(6)` `implies|d|=6` |
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