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If the distance between two objects is doubled, the gravitational force between them:A. remains the sameB. gets doubledC. gets halvedD. becomes one – fourth |
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Answer» If the distance between two objects is doubled the gravitational force becomes one fourth since, F = G\(\frac{m_1\times m_2}{R^2}\) Where R is the distance between the bodies. So, if R’ = 2R, then F' = G\(\frac{m_1\times m_2}{R'^2}\) F' = G\(\frac{m_1\times m_2}{4\times R^2}\) = \(\frac{F}{4}\) Hence, option D is correct. |
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