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If the `E^(@)` for a given reaction has a negative value, then which of the following gives the correct relationship for the of `DeltaG^(@)` and `k_(aq)`?A. `DeltaG^(ɵ) gt 0, K_(eq) lt 1`B. `DeltaG^(ɵ) gt 0, K_(eq) gt 1`C. `DeltaG^(ɵ) lt 0, K_(eq) gt 1`D. `DeltaG^(ɵ) lt 0, K_(eq) lt 1` |
Answer» Correct Answer - A `DeltaG=-nFE^(ɵ)` or `E^(@)=(-DeltaG)/(nF)` `:. DeltaG^(ɵ) gt 0` and `DeltaG^(ɵ)=-nRT In K_(p)` `:. K_(eq) lt1` |
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