1.

If the earth of radius R, while rotating with angular velocity to become standstill, what will be the effect on the weight of a body of mass m at a latitude of 45^(@)?

Answer»

REMAINS unchanged
decreases by `R omega^(2)`
increases by `R omega^(2)`
increases by `R omega^(2)//2`

Solution :`G.=g-Romega^(2)COS^(2)GAMMA`, when `gamma=45^(@)`,
thus `g.=g-R omega^(2)((1)/(sqrt(2))^(2))=g(Romega^(2))/(2)`
When earth stops rotating, `omega=0`, so g.=g
Increase in weight of body `=g-(g-(R omega^(2))/(2))=(R omega^(2))/(2)`


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