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If the earth were a homegeneous sphere and a straight hole was bored in it through its centre, so when a body is dropped in the hole, it will excutes SHM. Determine the time period of its oscillation . Radius of the earth is `6.4 xx 10^(5)` m and `g=9.8 ms^(-2)` |
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Answer» Given, R`=6.4 xx 10^(5)m ,g=9.8 ms^(-2)` `therefore` Time period of oscillation of body will be `T=2pisqrt((R)/(g))=2pisqrt((6.4xx10^(5))/(9.8))=1605.67 s` |
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