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if the electron in hydrogen orbit jumps form third orbit to second orbit, the wavelength of the emitted radiation is given byA. `lambda = ( R)/(6)`B. `lambda = (36)/(5 R)`C. `lambda = ( 6)/(R)`D. `lambda = (5 R)/(36)` |
Answer» Correct Answer - B `(1)/(lambda) = R [(1)/(2^(2)) - (1)/(3^(2))] = (5 R)/(36) : lambda = (36)/(5 R)` |
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