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If the energy of a hydrogen atom in `nth` orbit is `E_(n)`, then energy in the nth orbit of a singly ionised helium atom will beA. `4E_(n)`B. `E_(n)//4`C. `2E_(n)`D. `E_(n)//2` |
Answer» Correct Answer - A We have `E_(n) = (-2pi^(2)mK^(2)Z^(2)e^(4))/(n^(2)h^(2))`. For helium `Z = 2` hence requisite answer is `4E_(n)` |
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