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If the energy of a photon of sodium light (lambda=589 nm) equals the band gap of a semiconductor, calculate the minimum energy required to create hole-electron pair. |
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Answer» Solution :`E=E_g=(HC)/(LAMBDA)=(6.6xx10^(-34)xx3xx10^(8))/(589xx10^(-9))J` `=(6.6xx3xx10^(-17))/(589xx1.6xx10^(-19))EV, E=2.1eV` |
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