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If the enthalpy change for the reaction CH_4(g)+Cl_2(g)rarrCH_3Cl(g)+HCl(g), triangleH=-25 kcal. Bond energy of C-H is 20kcal/mol greater than the bond energy of C-Cl and bond energies of H-H and H-Cl are same in magnitude, then for the reaction: 1//2H_2(g)+1//2Cl_2(g)rarrHCl(g) triangleH is |
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Answer» `-22.5 kcal/mol` |
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