1.

If the enthalpy change for the transition of liquid water to steam is 30 kJ mol^(-1) at 27^(@)C, the entropy change for the process would be :

Answer»

`10 J mol^(-1) K^(-1)`
`1.0 J mol^(-1) K^(-1)`
`0.1 mol^(-1) K^(-1)`
`100 J mol^(-1) K^(-1)`

Solution :Liquid water `rarr` STEAM
`Delta S = (Delta H_("vap"))/(T) = (30 xx 10^(3) J mol^(-1))/(300 K)`
`= 100 J mol^(-1) K^(-1)`


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