1.

If the enthalpy change for the transition of liquid water to steam is 30 kJmol^(-1) at 27^(@)C, the entropy change for the process would be

Answer»

`100 J MOL^(-1) K^(-1)`
`10 J mol^(-1) K^(-1)`
`1.0 J mol^(-1) K^(-1)`
`0.1 J mol^(-1) K^(-1)`

Solution :`DeltaS_("vap")=(DeltaH_("vap"))/(T)=(30 KJ mol^(-1))/(300 K)=100 J mol^(-1) K^(-1)`.


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