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If the enthaply change for the transition of liquid water to steam is 30 KJ `"mol"^(-1)` at `27^(@)` C . The entropy change for the process would beA. `0.1 J mol^(-1) K^(-1)`B. `100 J mol^(-1) K^(-1)`C. `10 J mol^(-1) K^(-1)`D. `1.0 J mol^(-1) K^(-1)` |
Answer» Correct Answer - B `"Liquid water" to"Steam"` `DeltaG^(@)=DeltaH^(@)-TDeltaS^(@)` `=30xx10^(3)-TDeltaS` `:. DeltaS=(30xx10^(3))/(300)=100 J mol^(-1)K^(-1)` |
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