1.

If the equation 2x^2+5xy+3y^2+6x+7y+=0 represents a pair of lines, then the equation of pair of lines parallel to then and passing through the point (0,1) is

Answer»

`2x^2+5xy+3y^2+5x+6y=0`
`2x^2+5xy+3y^2+5x+6y+3=0`
`2x^2+5xy+3y^2+5x-6y+3=0`
`2x^2+5xy+3y^2+5x+6y+3=0`

ANSWER :C


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