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If the equation in x given by (2(1/(cos^(-1)x)))^(2pi)-(a+1/2)(2(1/(cos^(-1)x)))^pi-a^2=0has only one real solution then exhaustive set of values of 'a' is |
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Answer» `(-3,-1)` EQUATION becomes `t^2-(a+1/2)t-a^2=0` has ONE roots 2 or greater than 2 and other root LESS than 2, f(2) `le` 0. `rArr 4-(a+1/2)2-a^2 le 0` `a^2+2a-3 le 0` `(a+3)(a-1) le 0` `a ge -3` or `a le 1` |
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