If the equilibrium constant for the reaction `A_(2)+B_(2) hArr 2AB` is K, then the backward reaction, `AB hArr 1/2 A_(2)+1/2 B_(2)` the equilibrium constant is `1//K`.

If the equilibrium constant for the reaction `A_(2)+B_(2) hArr 2AB` is

1.	If the equilibrium constant for the reaction `A_(2)+B_(2) hArr 2AB` is K, then the backward reaction, `AB hArr 1/2 A_(2)+1/2 B_(2)` the equilibrium constant is `1//K`.
Answer» False. If the equilibrium constant for the reaction `AB hArr 1/2 A_(2)+1/2 B_(2)` the equilibrium constant is `sqrt(1//K)` because the reaction is reversed as well as divided by two.

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If the equilibrium constant for the reaction `A_(2)+B_(2) hArr 2AB` is K, then the backward reaction, `AB hArr 1/2 A_(2)+1/2 B_(2)` the equilibrium constant is `1//K`.

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