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If the equilibrium constant of the reaction `2HI(g)hArrH_(2)(g)+I_(2)(g)` is `0.25`, find the equilibrium constant of the reaction. `(1)/(2)H_(2)+(1)/(2)I_(2)hArrHI(g)` |
Answer» Correct Answer - 2 For reaction `H_(2)(g)I_(2)(g)hArr2HI(g) K"=(1)/(0.25)=4` For reaction `(1)/(2)H_(2)+(1)/(2)I_(2)hArrHI(g) K"=sqrt4` |
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