1.

If the equilibrium constant of the reaction `2HI(g)hArrH_(2)(g)+I_(2)(g)` is `0.25`, find the equilibrium constant of the reaction. `(1)/(2)H_(2)+(1)/(2)I_(2)hArrHI(g)`

Answer» Correct Answer - 2
For reaction
`H_(2)(g)I_(2)(g)hArr2HI(g) K"=(1)/(0.25)=4`
For reaction
`(1)/(2)H_(2)+(1)/(2)I_(2)hArrHI(g) K"=sqrt4`


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