If the equilibrium constant of the reaction `2HIhArrH_(2)+I_(2)is 0.25,` then the equlibrium constnat of the reaction `H_(2)+I_(2)hArr2HI` would beA. `1.0`B. `2.0`C. `3.0`D. `4.0`

If the equilibrium constant of the reaction `2HIhArrH_(2)+I_(2)is 0.25

1.	If the equilibrium constant of the reaction `2HIhArrH_(2)+I_(2)is 0.25,` then the equlibrium constnat of the reaction `H_(2)+I_(2)hArr2HI` would beA. `1.0`B. `2.0`C. `3.0`D. `4.0`
Answer» Correct Answer - D `K_(1)` for reaction `2HIhArr H_(2)+I_(2)is 0.25 K_(2)` for reaction `H_(2)+I_(2)hArr2HI "will be"K_(2)=(1)/(K_(1))=(1)/(0.25)=4` Because `II^(nd)` reaction is reverse of `I^(st).`

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If the equilibrium constant of the reaction `2HIhArrH_(2)+I_(2)is 0.25,` then the equlibrium constnat of the reaction `H_(2)+I_(2)hArr2HI` would beA. `1.0`B. `2.0`C. `3.0`D. `4.0`

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