1.

If the equilibrium constants of following reactions are 2A hArr B is K_(1) and B hArr2A is K_(2), then

Answer»

`K_(1)=2K_(2)`
`K_(1)=1//K_(2)`
`K_(2)=(K_(1))^(2)`
`K_(1)=1//K_(2)^(" "2)`

ANSWER :B


Discussion

No Comment Found

Related InterviewSolutions