1.

If the error in the measurement of momentum of a particle is (+100%), then the error in the measurement of kinetic energy is :

Answer»

<P>`250%`
`200%`
`300%`
`400%`

Solution :Relation between `E_(k)` and `p` is `E_(k)=(p^(2))/(2M).` When `p` is doubled, `E_(k)` becomes four times. So, `E_(k)` INCREASES by `300`.
`:.%` age increase `=(4E_(k)-E_(k))/(E_(k))XX100`
`=300%`
Hence `(c )` is CORRECT.


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