1.

If the escape velocity of a body on Earth is 11.2 km/s, the escape velocity of the body thrown at an angle 45° with the horizontal will be(A) 11.2 km/s(B) 22.4 km/s(C) \(\frac{11.2}{\sqrt{2}}\) km/s(D) 11.2 \(\sqrt{2}\) km/s

Answer»

Correct option is: (A) 11.2 km/s

Escape velocity does not depend on the angle of projection.

\(V_{escape} = \sqrt {2gRe} \)

Correct option is: (A) 11.2 km/s



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