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If the focal length of a magnifier is 5 cm, calculate (a) the power of the lens (b) the magnifying power of the lens for relaxed and strained eye. |
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Answer» SOLUTION :(a) As power of a LENS is reciprocal of focal LENGTH in m, `P=1/((5xx10^(-2)m))=1/0.05` dioptre = 20D (b) For relaxed eye, MP is minimum and will be MP = `D/f=25/5=5` While for strained eye, MP is MAXIMUM and will be MP = `1+D/f=1+5=6` |
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