InterviewSolution
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InterviewSolution
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If the force is given by `F=at+bt^(2)` with `t` is time. The dimensions of `a` and `b` areA. `[MLT^(-4)]` and `[MLT^(-2)]`B. `[MLT^(-3)` and `[MLT^(-4)]`C. `[ML^(2)T^(-3)]` and `[ML^(2)T^(-2)]`D. `[ML^(2)T^(-3)]` and `[ML^(3)T^(-4)]` |
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Answer» (b) Dimension of at `=` Dimension of `F` `[at]=[F]implies[a]=[F/t]` `[b]=[(MLT^(-2))/T]implies[a]=[MLT^(-3)]` Dimension of `bt^(2)=` Dimension of `F` `[bt^(2)]=[F]=[b]=[F/(t^(2))]` `[b]=[(MLT^(-2))/(T^(2))]implies[b]=[MLT^(-4)]` |
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