1.

If the frequency of incident light on a certain metal is 8.2xx10^(14)Hz, having threshold frequency 3.3xx10^(14)Hz, then cut off potential is :

Answer»

3. 0 V
4.0 V
5.1 V
None of these.

Solution :`(1)/(2) mv^(2)=H(v-v_(0))`
At V= CUT off potential,
`eV=(1)/(2) mv^(2)`
`:.V=(h(v-v_(0)))/(E)=2`volt


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