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If the frequency of revolution of a proton (q = 1.6 × 10-19C) in a uniform magnetic induction is 106 Hz, what is the corresponding electric current? |
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Answer» I = \(\cfrac{q}T\) = qf = (1.6 × 10-19)(106) = 1.6 × 10-13 A is the corresponding electric current. |
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