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if the g is the acceleration due to gravity on the surface of earth its value at a height equal to is double the radius of earth |
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Answer» Acceleration due to GRAVITY at a height h from the SURFACE of the earth$ g'=g\frac{1}{\LEFT(1+\frac{h}{R}\right)^2} $Given h=2R$ \THEREFORE $ $ g'=g\frac{1}{(1+2)^2} $or $ g'=\frac{g}{9} $ |
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