1.

If the given four electronic configurations (i) n = 4, l = 1 (ii) n = 4, I= 0 (iii) n = 3, l = 2 (iv) n = 3, I= 1 are arranged in order of increasing energy, then the order will be

Answer»

(iv)lt (ii)lt (iii) lt (i)
(ii)lt (iv)lt (i) lt (iii)
(i) lt (iii) lt (ii) lt (iv)
(iii) lt (i) lt (iv) lt (ii)

SOLUTION :(i) n = 4, l = 1 `rArr` 4p-orbital
(ii) n = 4, l = 0 `rArr` 4s-orbital
(iii) n = 3, l = 2 `rArr` 3D-orbital
(iv) n = 3, I= I `rArr` 3P-orbital
Increasing order of energy as PER (n +l)rule :
3p < 4s < 3d < 4p
(iv) (ii) (iii) (i)


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