1.

If the gravitional force between two objects were proportional to 1/R (and not as 1R^(2)) where R is separation between them , then a particle in circular orbit under such a force would have its orbital speed v proportional to

Answer»

`R^(1)`
`1//R`
`R^(0)`
`1//R^(2)`

Solution :Gravitational FORCE PROVIDES necessary centripetal force
`therefore (GMm)/(R )=(mv^(2))/(R )`
`rArr v=sqrt(GM)`.
i.e. v is independent of R.
THUS correct CHOICE is (c ).


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