1.

If the half-life period of a first order reaction is 138.6 minutes, then the value of decay constant for the reaction will be

Answer»

`5 "miniute"^(-1)`
`0.5 "MINUTE"^(-1)`
`0.05 "minute"^(-1)`
`0.005 "minute"^(-1)`

Solution :`K = (0.693)/(t_(1//2)) = (0.693)/(138.6 "MIN") = 0.005 "min"^(-1)`


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