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If the heat change at constant volume for decomposition of silver oxide is 80.25 kJ, what will be the heat change at constant pressure ?A. 80.25 kJB. gt 80.25kJC. lt 80.25 kJD. 160.50 kJ

Answer» Correct Answer - B
`Ag_(2)O_((s)) rarr 2Ag_((s))+(1)/(2)O_(2(g)),q_(v)=DeltaU=80.25kJ`
`q_(p)=q_(v)+Deltan_(g)RT`
`Deltan_(g) gt 0((1)/(2)-0=(1)/(2)) or q_(p) gt q_(v) or q_(p) gt 80.25kJ`


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