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If the heat fo dissolution of anhydrous `CuSO_(4)` and `CuSO_(4).5H_(2)O` is `-15.89 kcal` and `2.80 kcal`, respectively, then the heat of hydration fo `CuSO_(4)` to form `CuSO_(4).5H_(2)O` isA. `-13.09 kcal`B. `-18.69 kcal`C. `+13.09 kcal`D. `+18.69kcal` |
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Answer» `CuSO_(4)(s)+aq rarr CuSO_(4).5H_(2)O,DeltaH^(Theta) =- 15.89 kcal` `CuSO_(4).5H_(2)O +aq rarr CuSO_(4).5H_(2)O,DeltaH^(Theta) =- 2.80 kcal` Heat of hydration `=- 15.89 - 2.80 =- 18.69 kcal` |
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