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If the initial velocity of an object thrown upwards is 14 m/s, then the time taken for theobject to reach its highest point will be(a9.8 m/s*) |
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Answer» Here we use first equation of motion, v=u+atat the highest point, final velocity, v would be zero.Initial velocity, u=14m/sa=-9.8 m/s ( negative sign as it acts downwards, opposite to the direction of velocity which here we have taken positive)so, 0= 14-9.8*ttherefore, 14=9.8tso, t=14÷9.8= 1.428 s= 1.43 s |
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