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if the intensity of the principal maximum in the single slit Fraunhoffer diffraction pattern, then the intensity when the slit width is double will be ..... |
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Answer» `I_(0)` `I_(theta)=I_(0)=(sin^(2) alpha)/(alpha) "" [ "where" alpha=(pi d sin theta)/(lambda)]` `:.` For central maximum `alpha=(pi(2d)sin theta^(0))/(lambda)` `alpha=0` `:. I_(theta)=I_(0)=(lim_(alpha to 0)(sin alpha)/(alpha))^(2)` `=I_(0)"" [ :. lim_(alpha to 0)(sin alpha)/(alpha)=1]` Short method : Maximum intensity depend on source of light. Here source is unchanged hence maximum intensity ALSO cannot CHANGED. |
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