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If the ionisation energy of hydrogen atom is 13.6 eV, the energy required to excite it from ground state to the next higher state is nearly |
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Answer» Solution :`E_(N)=-(13.6)/(n^(2))eV,DeltaE=E_(2)-E_(1)` `=-13.6(1/(2^(2))-1/(1^(2)))=13.6xx3/4=10.2eV` |
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