If the K.E. of free electron doubles, its de-Broglie wavelength change

1.	If the K.E. of free electron doubles, its de-Broglie wavelength changes by the factor
Answer» `(1)/(2)` 2 `(1)/(SQRT(2))` `sqrt(2)` Solution :`lambda = (H)/(sqrt(2mK))` When kinetic energy is doubled, `lambda. = (h)/(sqrt(2m XX 2K)) = (1)/(sqrt(2)) lambda`

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In which accelerated motion, K.E of the particle is constant

If the K.E. of free electron doubles, its de-Broglie wavelength changes by the factor

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