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If the kinetic energy of a free electron doubles , its de - Broglie wavelength changes by the factorA. `(1)/(2)`B. `2`C. `(1)/(sqrt(2))`D. `sqrt(2)` |
Answer» Correct Answer - C We know `lambda=(h)/(m v)` and `K=(1)/(2) mv^(2)=((3v)^(2))/(2m)` `rArrmv=sqrt(2mK)` Thus `lambda=(h)/(sqrt(2mK))` `rArr lambda prop (1)/(sqrt(K))` `:. (lambda_(2))/(lambda_(1))=sqrt(K_(1))/(sqrt(K_(2)))= sqrt(2K_(1))/(sqrt(2K_(1))) " "( :. K_(2)=2K_(1))` `rArr (lambda_(2))/(lambda)=(1)/(sqrt(2))` `:. lambda_(2)=(1)/(sqrt(2))` |
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