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If the kinetic energy of a free electron doubles , its de - Broglie wavelength changes by the factorA. `1/2`B. `2`C. `1/(sqrt(2))`D. `sqrt(2)` |
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Answer» Correct Answer - C The de-Brogile wavelengths and kinetic energy of a free electron are related as `lambda=h/sqrt(2mK)implies lambda_(2)/lambda_(1)=sqrt(K_(1)/K_(2))=sqrt(1/2)implies lambda_(2)=lambda_(1)/sqrt(2)` |
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