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if the length of a conductor is increased by 10% on stretching what will be the effect on its new resistance |
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Answer» Answer: If VOLUME and density REMAINS same, then resistance of WIRE: R∝l2 where L is length of the wire ∴R′=(1+10010l)2=(1011)2R Hence, RR′−R=10021=21% Therefore, change in resistance of wire = 21% Explanation: please upvote |
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