If the length of a simple pendulum is increased by 2%, then the time p

1.	If the length of a simple pendulum is increased by 2%, then the time period
Answer» increases by 1% DECREASES by 1% increases by 2% decreases by 2% Solution :`l_(2) = 1.02 l_(1)`, Time period (T) `=2pi xx sqrt(l/g) prop sqrt(l)` THEREFORE `T_(2)/T_(1) = sqrt(I_(2)/I_(1)) = sqrt((1.02 l_(1))/l_(1)) = 1.01` THUS, time period INCREASED by 1%.

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If the length of a simple pendulum is increased by 2%, then the time period

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