If the length of diagonals in cm of a rhombus are 6x and 8x and its pe

1.	If the length of diagonals in cm of a rhombus are 6x and 8x and its perimeter is 40 cm, then value of 2x is?please answer this
Answer» Answer: mark me brainlinest and thank me plzzzz my name is shivanya if u like my answer PLZ CHAT also Step-by-step explanation: Let the unit be x so the diagonals are 6x and 8x let the shorter diagonal be 6x and longer be 8x the point of intersection of the two digonals to be named as O so half of the diagonals be 6x/2 and 8x/2 given pmt=40cm one side=40÷4=10 cm so all the sides are 10cm respectively (as in Rhombus all the sides are of equal measure) so According to pythagoras theorm (6x/2)^2 +(8x)^2 =(10)^2 36x^2/4+64x^2/4=100 100x^2=100×4 100x^2=400 x^2=4 x=2 so LENGTH of shorter side is 6x=6×2=12 so length of longer side is 8x = 8 x 2= 16

If the length of diagonals in cm of a rhombus are 6x and 8x and its perimeter is 40 cm, then value of 2x is?please answer this

Answer»

Answer:

mark me brainlinest and thank me plzzzz

my name is shivanya if u like my answer PLZ CHAT also

Step-by-step explanation:

Let the unit be x so the diagonals are 6x and 8x

let the shorter diagonal be 6x and longer be 8x

the point of intersection of the two digonals to be named as O

so half of the diagonals be 6x/2 and 8x/2

given pmt=40cm

one side=40÷4=10 cm

so all the sides are 10cm respectively (as in Rhombus all the sides are of equal measure)

so According to pythagoras theorm

(6x/2)^2 +(8x)^2 =(10)^2

36x^2/4+64x^2/4=100

100x^2=100×4

100x^2=400

x^2=4

x=2

so LENGTH of shorter side is 6x=6×2=12

so length of longer side is 8x = 8 x 2= 16