1.

If the length of second's pendulum is increased by 2%, how many seconds it loses per day ?

Answer»

3927 s
1728 s
3427 s
864 s.

Solution :`T=2pi sqrt(l//g)` and `T.=2pi sqrt((102l)/(100G))`
`:.""(T.)/(T)=sqrt((102)/(100))impliesT.=2[1+(2)/(100)]^(1//2)`
or `""T.=2[1+(1)/(100)]=2+(2)/(100)`
Loss in TIME `=2+(2)/(100)-2=(2)/(100)` s.
`:.`Loss in time for 2 s `=(2)/(100)`
Loss in timefor DAY `=(2)/(100)xx(86400)/(2)=864` s.
Hencecorrectchoice is (d).


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